assume the random variable x is normally distributed with mean 80 and standard deviation 4. Find the indicated Probability P (70<×<76)
Solution:
We are given that the random variable X is normally distributed.
Mean = 80
SD = 4
We have to find P(70<X<76)
P(70<X<76) = P(X<76) – P(X<70)
First find P(X<76)
Z = (X – mean) / SD
Z = (76 – 80)/4 = -4/4 = -1
P(Z<-1) = 0.158655
(by using z-table or excel)
P(X<76) = 0.158655
Now find P(X<70)
Z = (70 – 80) / 4
Z = -2.5
P(Z<-2.5) = 0.00621
(by using z-table or excel)
P(X<70) = 0.00621
P(70<X<76) = P(X<76) – P(X<70)
P(70<X<76) = 0.158655 - 0.00621
P(70<X<76) = 0.152445
Required probability = 0.152445
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