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Let X, the amount of money a student at a university spent on rent in April...

Let X, the amount of money a student at a university spent on rent in April 2013, be normally distributed with mean $500 and standard deviation $100. Then, there is a 95% probability that a randomly selected student spent between 500 − (1.96 × 100) = 304 and 500 + (1.96 × 100) = 696 dollars on rent in April 2013.

Check if this is correct: Here, X is normally distributed with μ = 500, σ = 100.

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