suppose the population average amount of dog biscuits in a bag is 40 pounds with a standard deviation of 6 pounds. a simple random sample of 64 bags is selected. what is the probability the sample mean weight will be within 1.5 pounds of the population mean?
Solution :
Given that,
mean = = 40
standard deviation = = 6
= / n = 6 / 64 = 0.75
= P[(-1.5) / 0.75< ( - ) / < (1.5) / 0.75)]
= P(-2 < Z < 2)
= P(Z < 2) - P(Z < -2)
= 0.9772 - 0.0228
= 0.9544
Probability = 0.9544
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