Consider the following gasoline sales time series data.
Week | Sales (1000s of gallons) |
1 | 18 |
2 | 22 |
3 | 20 |
4 | 24 |
5 | 17 |
6 | 15 |
7 | 19 |
8 | 17 |
9 | 23 |
10 | 19 |
11 | 14 |
12 | 23 |
a. Using a weight of 1/2 for the most recent observation, 1/3 for the second most recent observation, and 1/6 third the most recent observation, compute a three-week weighted moving average for the time series (to 2 decimals). Enter negative values as negative numbers.
Week |
Time-Series Value |
Weighted Moving Average Forecast |
Forecast Error |
(Error)2 |
||
1 | ||||||
2 | ||||||
3 | ||||||
4 | ||||||
5 | ||||||
6 | ||||||
7 | ||||||
8 | ||||||
9 | ||||||
10 | ||||||
11 | ||||||
12 | ||||||
Total |
b. Compute the MSE for the weighted moving
average in part (a).
MSE = ?
Do you prefer this weighted moving average to the unweighted
moving average? Remember that the MSE for the unweighted moving
average is 17.43.
Prefer the unweighted moving average here; it has a - Select your
answer -(greater/smaller) MSE.
c. Suppose you are allowed to choose any
weights as long as they sum to 1. Could you always find a set of
weights that would make the MSE at least as small for a weighted
moving average than for an unweighted moving average?
- Select your answer -(Yes/No)
a)
week | sales | forecast | error | error^2 |
1 | 18 | |||
2 | 22 | |||
3 | 20 | |||
4 | 24 | 20.33 | 3.67 | 13.44 |
5 | 17 | 22.33 | -5.33 | 28.44 |
6 | 15 | 19.83 | -4.83 | 23.36 |
7 | 19 | 17.17 | 1.83 | 3.36 |
8 | 17 | 17.33 | -0.33 | 0.11 |
9 | 23 | 17.33 | 5.67 | 32.11 |
10 | 19 | 20.33 | -1.33 | 1.78 |
11 | 14 | 20.00 | -6.00 | 36.00 |
12 | 23 | 17.17 | 5.83 | 34.03 |
total | 172.64 | |||
average | 19.18 |
b)
MSE =19.18
unweighted moving average as its MSE is smaller
c)
Yes
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