A sample of 81 students has a mean GPA of 3.25. The sample is normally distributed, and the population standard deviation is found to be 0.63 grade points. Find the Lower Limit of the 95% confidence interval. (express your answers rounded to two decimal places)
Solution :
Given that,
Sample size = n = 81
Z = 1.645
Margin of error = E = Z* ( /n)
= 1.645 * (0.63 / 81)
Margin of error = E = 0.12
At 95% lower confidence interval estimate of the population mean is,
- E
3.25 - 0.12
3.13
Lower limit: 3.12
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