Of the 400 people signed up for the webinar only 300 actually attended.
What are the odds of picking someone who attended the webinar out of the 400 people?
Group of answer choices
a) 3 to 1
b) .75 to 1
c) 1 to 3
d) 3 to 4
What distribution would best model the sampling distribution with a sample proportion of p-hat = .5 and with a sample size of 50?
Group of answer choices
a)z-distribution
b)normal distribution
c)chi-square distribution
d)t-distribution
Use the following two-way table to answer this question.
What is your employment status?
Full-time | Doesn't work | Part-time | |
World Campus Student | 4 | 10 | ? |
UP Student | 20 | 50 | 30 |
If there is no association between working status and type of student, what would you expect to be in the missing cell [part time, WC students]?
Group of answer choices
a)10
b)30
c)14
d)6
Of the 400 people signed up for the webinar only 300 actually attended.
What are the odds of picking someone who attended the webinar out of the 400 people?
P[ attended the webinar ] = 300/400
P[ attended the webinar ] = 3/4
hence the odds are
d) 3 to 4
What distribution would best model the sampling distribution with a sample proportion of p-hat = .5 and with a sample size of 50?
As n = 30
p = 0.5
q = 1 - p = 1 - 0.5 = 0.5
np = 30*0.5 = 6 > 5
nq = 30*0.5 = 6 > 5
Hence the distribution is normal
b)normal distribution
If there is no association between working status and type of student, what would you expect to be in the missing cell [part time, WC students]?
No association means the ratio remains same
4/20 = 1/5
10/50 = 1/5
x/30 = 1/5
x = 30/5
x = 6
d) 6
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