An engineer is going to redesign an ejection seat for an
airplane. The seat was designed for pilots weighing between 150 lb
and 201 lb. The new population of pilots has normally distributed
weights with a mean of 157 lb and a standard deviation of 29.7
lb.
a. If a pilot is randomly selected, find the probability that his
weight is between 150 lb and 201 lb.
Solution :
Given that,
mean = = 157
standard deviation = = 29.7
P (150 < x < 201 )
P ( 150 - 157 / 29.7) < ( x - / ) < ( 201 - 157 / 29.7)
P ( - 7 / 29.7 < z < 44 / 29.7 )
P (-0.23 < z < 1.48 )
P ( z < 1.48 ) - P ( z < -0.23)
Using z table
= 0.9306 - 0.4090
= 0.5216
Probability = 0.5216
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