Question

Dr. Penn is investigating the difference in depression scores between introverts and extraverts. The sample size...

Dr. Penn is investigating the difference in depression scores between introverts and extraverts. The sample size for introverts was n=15, and the sample size for extraverts was n=20. If the researcher found that the t value for this analysis was equal to t=2.00, what conclusion should you make for an alpha of 0.05, two tails?

Homework Answers

Answer #1

We are given the value of

We are also given

Hence the degrees of freedom are

The level of significance alpha is equal to 0.05.

At 5% level of significance and 33 d.o.f, the critical t-Value (two-tailed): +/- 2.034515

Since

we fail to reject the null hypothesis and conclude that the depression scores between introverts and extraverts is the same at a 5% level of significance.

Let me know in the comments if anything is not clear. I will reply ASAP! Please do upvote if satisfied!

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Pick the best choice A researcher compared a sample of BYC students (n = 10) and...
Pick the best choice A researcher compared a sample of BYC students (n = 10) and a sample of GYC students (n = 10) on the hours of sleep. After computing the difference between the two groups, he found t= 1.50. Using α= .05 two tails, what is his conclusion? *Failed to reject the null hypothesis, and there is no difference between two groups on the sleep hours. *Reject the null hypothesis, and there is a difference between two groups...
A therapist would like to evaluate an intervention for treating depression. A sample of n =...
A therapist would like to evaluate an intervention for treating depression. A sample of n = 20 depressed clients is obtained, and each person’s level of depression is measured using a standardized questionnaire before they begin the therapy program. Two weeks after therapy, each client’s level of depression is measured again. The average level of depression dropped by 4.0 points following therapy. The difference scores had a variance of 64. a. State the null hypothesis. b.            Identify the appropriate statistical...
A therapist would like to evaluate an intervention for treating depression. A sample of n =...
A therapist would like to evaluate an intervention for treating depression. A sample of n = 20 depressed clients is obtained, and each person’s level of depression is measured using a standardized questionnaire before they begin the therapy program. Two weeks after therapy, each client’s level of depression is measured again. The average level of depression dropped by 4.0 points following therapy. The difference scores had a variance of 64. a. State the null hypothesis. b. Identify the appropriate statistical...
Statistical power analysis seeks to optimize the size of the ___________. difference sample population correlation Statistical...
Statistical power analysis seeks to optimize the size of the ___________. difference sample population correlation Statistical power is the likelihood that an effect will be detected in the sample when one ____________. is hypothesized to exist has been found in previous research really exists exists in a previous sample of the same population The probability of failing to detect an effect when one exists is known as a _______. Type I error Type II error Power Standardized error Which of...
You want to test your hypothesis below: There is a difference in mean test scores between...
You want to test your hypothesis below: There is a difference in mean test scores between before practice and after practice.             Provide your answers in the template below the data set. Before After 13 16 16 18 10 12 14 18 15 18 12 15 11 12 18 20 19 20 16 18 15 18 14 15 12 12 13 17 14 16 15 17 State the Ha= State the H0= Before After Mean SD t-test, p value Conclusion...
The null hypothesis states there will be no difference in scores on the ADS between those...
The null hypothesis states there will be no difference in scores on the ADS between those who receive the standard treatment program and those who receive the standard treatment program plus Mindfulness Therapy. The output from the analysis is below. The results are t(19) = 1.554, p = .137. Paired Sample Statistics Mean N Std Deviation Std. Error Mean Pair 1 Standard Std. Mindfulness 12.8000 10.9500 20 20 3.81962 4.28553 .85409 .95827 Paired Samples Correlations N Correlations Sig Pair 1...
Researchers wants to know if taking the herbal supplement St. John's Wort will affect depression. First,...
Researchers wants to know if taking the herbal supplement St. John's Wort will affect depression. First, they measure the depression level of a sample of n = 4 depressed people (Pre-Test Scores). Then after a week of taking St. John's Wort, they again measure the sample's depression levels (Post-Test Scores). Note that high scores on the depression measure indicate more depression, whereas low scores indicate less depression. Participant Pre-Test Scores Post-Test Scores A 9 6 B 12 5 C 13...
Dr. Calvin Broadus wants to determine whether marijuana influences anxiety. He draws a sample of n...
Dr. Calvin Broadus wants to determine whether marijuana influences anxiety. He draws a sample of n = 16 individuals. The population from which they were selected exhibit a score of µ = 30 on an anxiety measure. After “treatment” is administered to the individuals, the sample mean is found to be M = 33 and the sample variance is s2 = 64. Is this a one-tailed or two-tailed test? One-tailed Two-tailed If the researcher decides to test at the α...
A researcher wants to prove that there is a difference in the average life spans between...
A researcher wants to prove that there is a difference in the average life spans between men and women in Japan. Let mu1 = average life span of Japanese women and mu2 = average life span of Japanese men. A random sample of 10 women showed an average lifespan of 83 years, with a sample standard deviation of 7 years. A random sample of 10 men showed an average lifespan of 77 years, with a sample standard deviation of 6.4...
If the outcome of a repeated-measures t test is reported as t(23) = 2.76, what is...
If the outcome of a repeated-measures t test is reported as t(23) = 2.76, what is the correct conclusion for an experiment that tested the effect of meditation on memory? A. The data showed a significant effect meditation on memory with p < .05 but no significant effect with p < .01, 2-tails test. B. The data showed a significant effect of meditation on memory with p < .05 and p < .01, 2-tails test. C. The data showed a...