Question

From the given information in each case below, state what you know about the P-value for a chi-square test and give the conclusion for a significance level of ? = 0.01. Use Table 8 in Appendix A.

(a) X² = 5, df = 2
< P-value <  
Conclusion:

Reject H₀

Fail to reject H₀    

(b) X² = 12.1, df = 6
< P-value <  
Conclusion:

Reject H₀

Fail to reject H₀    

(c) X² = 21.24, df = 9
< P-value <  
Conclusion:

Reject H₀

Fail to reject H₀    

(d) X² = 20.92, df = 4
P-value  ---Select--- < > =  
Conclusion:

Reject H₀

Fail to reject H₀    

(e) X² = 5.3, df = 3
P-value  ---Select--- < = >  
Conclusion:

Reject H₀

Fail to reject H₀   

Answer 1

(a) X2 = 5, df = 2
Using Table 8 in appendix A, we got P value = 0.0821

So, P value

Conclusion: Fail to reject null hypothesis because p value is insignificant.

(b) X2 = 12.1, df = 6

Using Table 8 in appendix A, we got P value = 0.0598

So, P value

Conclusion: Fail to reject null hypothesis because p value is insignificant.

(c) X2 = 21.24, df = 9

Using Table 8 in appendix A, we got P value = 0.0116

So, P value

Conclusion: Fail to reject null hypothesis because p value is insignificant.

(d) X2 = 20.92, df = 4

Using Table 8 in appendix A, we got P value = 0.0003

So, P value

Conclusion: Reject null hypothesis because p value is significant.

(e) X2 = 5.3, df = 3

Using Table 8 in appendix A, we got P value = 0.1511

So, P value

Conclusion: Fail to reject null hypothesis because p value is insignificant.