: Consider the test of H0 : p = 0.7 Vs. Ha : µ > 0.7 using a random sample of 400 values and α = 1%. Find the power of the test when pa = 0.75.
The power of the test is computed as the probability of
rejecting the null hypothesis when it is false Here as this is a
one tailed test, we get from the standard normal tables,
P(Z > 2.326) = 0.01
Therefore the critical p - value here is computed as:
Therefore now we are rejecting the null hypothesis here when p >= 0.7533
Therefore the power of the test given the true proportion is 0.75 is computed here as:
P( p > 0.7533)
Converting it to a standard normal variable, we get here:
Getting it from the standard normal tables, we get here:
Therefore 43.94% is the required power of the test here.
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