Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to determine of the mean number of unoccupied seats on all its flights is greater than 10. To accomplish this, the records of 60 flights are randomly selected and the number of unoccupied seats is noted for each of the sampled flights.
The sample mean is 10.4 seats and the sample standard deviation is 3.4 seats. Test the claim that mean number of unoccupied seats on all its flights is greater than 10 at the 5% significance level.
Solution :
= 10
=10.4
S =3.4
n = 60
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : = 10
Ha : >10
Test statistic = t
= ( - ) / S / n
= (10.4-10) / 3.4 / 60
= 0.911
Test statistic = t = 0.911
P-value = 0.1829
= 0.05
P-value >
0.1829 > 0.05
Do not reject the null hypothesis .
There is insufficient evidence to suggest that
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