A random sample of 20 statistics examinations was taken. The average score, in the sample, was 84 with a standard deviation of 3.5. Develop a 95% confidence interval for the average examination score of the population of the examinations.
a. The critical value for the confidence interval (Provide 3 decimals)
b. Lower limit (Provide 2 decimals)
c. Upper limit (Provide 2 decimals)
Solution :
Given that,
a.
t /2,df = 2.093
Margin of error = E = t/2,df * (s /n)
= 2.093 * (3.5 / 20)
Margin of error = E = 1.64
The 95% confidence interval estimate of the population mean is,
- E < < + E
84 - 1.64 < < 84 + 1.64
82.36 < < 85.64
b. Lower limit: 82.36
c. Upper limit 85.64
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