Question

If the inspection division of a county weights and measures department wants to estimate the mean...

If the inspection division of a county weights and measures department wants to estimate the mean amount of? soft-drink fill in? 2-liter bottles to within plus or minus0.02 liter with 95?% confidence and also assumes that the standard deviation is 0.09 ?liters, what sample size is? needed?

Homework Answers

Answer #1

Solution :

Given that,

standard deviation = = 0.09

margin of error = E = 0.02

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.960

Sample size = n = ((Z/2 * ) / E)2

= ((1.960 * 0.09) / 0.02)2

= 77.79

Sample size = 78

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The inspection division of the Lee County Weights and Measures Department is interested in estimating the...
The inspection division of the Lee County Weights and Measures Department is interested in estimating the actual amount of soft drink that is placed in 2-liter bottles at the local bottling plant of a large nationally known soft-drink company. The bottling plant has informed the inspection division that the standard deviation for 2-liter bottles is 0.05 liter, i.e. the population standard deviation is σ = 0.05. A random sample of one hundred 2-liter bottles obtained from this bottling plant indicates...
If the manager of a bottled water distributor wants to​ estimate, with 95​% ​confidence, the mean...
If the manager of a bottled water distributor wants to​ estimate, with 95​% ​confidence, the mean amount of water in a​ 1-gallon bottle to within ±0.002 gallons and also assumes that the standard deviation is 0.05 ​gallons, what sample size is​ needed?
The fill amount in 1​-liter soft drink bottles is normally​ distributed, with a mean of 1.0...
The fill amount in 1​-liter soft drink bottles is normally​ distributed, with a mean of 1.0 liter and a standard deviation of 0.05 liter. If bottles contain less than 95​% of the listed net content ​(0.95 ​liters, in this​ case), the manufacturer may be subject to penalty by the state office of consumer affairs. Bottles that have a net content above 1.08 liters may cause excess spillage upon opening. In an effort to reduce the number of bottles that contain...
An advertising executive wants to estimate the mean weekly amount of time consumers spend watching traditional...
An advertising executive wants to estimate the mean weekly amount of time consumers spend watching traditional television daily. Based on previous​ studies, the standard deviation is assumed to be 24 minutes. The executive wants to​ estimate, with​ 99% confidence, the mean weekly amount of time to within plus or minus ±66 minutes. a. What sample size is​ needed? b. If​ 95% confidence is​ desired, how many consumers need to be​ selected?
Please, complete the following exercises: 1. A Quality Control inspector wants to estimate the true population...
Please, complete the following exercises: 1. A Quality Control inspector wants to estimate the true population mean for the diameter of an extruded plastic rod. She samples 65 rods. The mean diameter is 2.18 inches. From previous work, the population standard deviation is known to be 0.2 inches. Find a 95% confidence interval for the true mean diameter of all plastic rods. 2.You work in Human Resources at Merrill Lynch. You plan to survey employees to find their average medical...
A company that produce soap wants to estimate the mean amount of the excess weight of...
A company that produce soap wants to estimate the mean amount of the excess weight of soap in a “1000-gram” bottle at a 99% confidence. The company knows that the standard deviation of the excess weight in all such soap bottles is 169 grams. How large a sample should the company select so that the estimate is within 1.5 grams of the population mean?
(a) A senatorial candidate wants to estimate the proportion of people in his voting district who...
(a) A senatorial candidate wants to estimate the proportion of people in his voting district who will favour a balanced-budget amendment, which is debatable. He wants this estimate to be within 0.03 of the population proportion for a 98%98% confidence interval. What is the sample size needed to produce this level of accuracy? (b) A researcher wants to make a 95%95% confidence interval for the population mean. The population standard deviation is 25.5025.50. What sample size is required so that...
A compensation analyst for an investment bank wants to estimate the mean hourly wages of several...
A compensation analyst for an investment bank wants to estimate the mean hourly wages of several hundred employees in the first 5 pay bands plus or minus within plus or minus $20. Management wants a 99% confidence level for the analysis. Assume that the population standard deviation is known to be $40 and that hourly wages are normally distributed. Find the minimum sample size required for this analysis.
A company wants to estimate the mean length the machine is cutting the plastic within 0.125...
A company wants to estimate the mean length the machine is cutting the plastic within 0.125 inch. Determine the minimum sample size required to construct a 95% confidence interval for the population mean. Assume the population standard deviation is 0.25 inch.?
4. The department of finance of Wells Fargo Bank wants to estimate the amount of an...
4. The department of finance of Wells Fargo Bank wants to estimate the amount of an annual healthcare premium needed for an investor banker as part of a new recruiting program. In a sample of 75 investor bankers, they found that the average yearly premium needed is $28,500 with a standard deviation of $3,500. (a) What is the population mean? What is the best estimate of the population mean? (b) Develop an 80% confidence interval for the population mean. (c)...