A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time students spent studying per week. They sampled 240 students and found a mean of 22.3 hours per week. Assuming a population standard deviation of six hours, what is the confidence interval at the 95% level of confidence? (Please use Student's t distribution at infinite degrees of freedom for three decimal accuracy of the required z value.)
a. 21.54 and 23.06
b. 21.80 and 22.80
c. 20.22 and 22.0
d. 16.3 and 28.3
The answer is:
We need to construct the 95% confidence interval for the population mean μ. The following information is provided:
Sample Mean = | 22.3 |
Population Standard Deviation (σ) = | 6 |
Sample Size (N) = | 240 |
The critical value for α=0.05 is
The corresponding confidence interval is computed as shown below:
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