Question

A random sample of n1 = 150 people ages 16 to 19 were taken from the...

A random sample of n1 = 150 people ages 16 to 19 were taken from the island of Oahu, Hawaii, and 14 were found to be high school dropouts. Another random sample of n2 = 137people ages 16 to 19 were taken from Sweetwater County, Wyoming, and 5 were found to be high school dropouts. Do these data indicate that the population proportion of high school dropouts on Oahu is different (either way) from that of Sweetwater County? Use a 1% level of significance.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: p1 = p2; H1: p1 < p2H0: p1 = p2; H1: p1p2     H0: p1p2; H1: p1 = p2H0: p1 = p2; H1: p1 > p2


(b) What sampling distribution will you use? What assumptions are you making?

The standard normal. The number of trials is sufficiently large.The Student's t. The number of trials is sufficiently large.     The standard normal. We assume the population distributions are approximately normal.The Student's t. We assume the population distributions are approximately normal.


What is the value of the sample test statistic? (Test the difference p1p2. Do not use rounded values. Round your final answer to two decimal places.)


(c) Find (or estimate) the P-value. (Round your answer to four decimal places.)


Sketch the sampling distribution and show the area corresponding to the P-value.


(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level α?

At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.     At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.


(e) Interpret your conclusion in the context of the application.

Reject the null hypothesis, there is sufficient evidence that the proportion of high-school dropouts on Oahu differs from that of Sweetwater County.Fail to reject the null hypothesis, there is insufficient evidence that the proportion of high-school dropouts on Oahu differs from that of Sweetwater County.     Fail to reject the null hypothesis, there is sufficient evidence that the proportion of high-school dropouts on Oahu differs from that of Sweetwater County.Reject the null hypothesis, there is insufficient evidence that the proportion of high-school dropouts on Oahu differs from that of Sweetwater County.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Sociologists wish to determine if the high school drop out rate in Sweetwater County, Wyoming is...
Sociologists wish to determine if the high school drop out rate in Sweetwater County, Wyoming is different from that in Oahu, Hawii. Using a 1% level of significance, they determined that they should fail to reject the null hypothesis. Give the interpretation of this conclusion. At the 1% level of significance, it appears that the population proportion of high school dropouts in Oahu is higher than that in Sweetwater County. At the 1% level of significance, it appears that the...
For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a...
For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a second independent binomial experiment, n2 = 100 binomial trials produced r2 = 50 successes. At the 5% level of significance, test the claim that the probabilities of success for the two binomial experiments differ. (a) Compute the pooled probability of success for the two experiments. (Round your answer to three decimal places.) (b) Check Requirements: What distribution does the sample test statistic follow? Explain....
For one binomial experiment, n1 = 75 binomial trials produced r1 = 45 successes. For a...
For one binomial experiment, n1 = 75 binomial trials produced r1 = 45 successes. For a second independent binomial experiment, n2 = 100 binomial trials produced r2 = 65 successes. At the 5% level of significance, test the claim that the probabilities of success for the two binomial experiments differ.(a) Compute the pooled probability of success for the two experiments. (Round your answer to three decimal places.) (b) Check Requirements: What distribution does the sample test statistic follow? Explain. The...
A random sample of n1 = 49 measurements from a population with population standard deviation σ1...
A random sample of n1 = 49 measurements from a population with population standard deviation σ1 = 3 had a sample mean of x1 = 13. An independent random sample of n2 = 64 measurements from a second population with population standard deviation σ2 = 4 had a sample mean of x2 = 15. Test the claim that the population means are different. Use level of significance 0.01. (a) Check Requirements: What distribution does the sample test statistic follow? Explain....
For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a...
For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a second independent binomial experiment, n2 = 100 binomial trials produced r2 = 50 successes. At the 5% level of significance, test the claim that the probabilities of success for the two binomial experiments differ. (a) Compute the pooled probability of success for the two experiments. (Round your answer to three decimal places.) (b) Check Requirements: What distribution does the sample test statistic follow? Explain....
For one binomial experiment, n1 = 75 binomial trials produced r1 = 45 successes. For a...
For one binomial experiment, n1 = 75 binomial trials produced r1 = 45 successes. For a second independent binomial experiment, n2 = 100 binomial trials produced r2 = 65 successes. At the 5% level of significance, test the claim that the probabilities of success for the two binomial experiments differ. (a) Compute the pooled probability of success for the two experiments. (Round your answer to three decimal places.) (b) Check Requirements: What distribution does the sample test statistic follow? Explain....
A random sample of n1 = 49 measurements from a population with population standard deviation σ1...
A random sample of n1 = 49 measurements from a population with population standard deviation σ1 = 5 had a sample mean of x1 = 8. An independent random sample of n2 = 64 measurements from a second population with population standard deviation σ2 = 6 had a sample mean of x2 = 11. Test the claim that the population means are different. Use level of significance 0.01.(a) Check Requirements: What distribution does the sample test statistic follow? Explain. The...
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 10.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.    No, the x distribution...
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 13 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 12.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.    No, the x distribution...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample...
A random sample of 36 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 14 and the sample standard deviation is 2. Use a level of significance of 0.05 to conduct a two-tailed test of the claim that the population mean is 13.5. (a) Is it appropriate to use a Student's t distribution? Explain. Yes, because the x distribution is mound-shaped and symmetric and σ is unknown.No, the x distribution is skewed left.    No, the x distribution...