Question

a) Find the AD (Anderson-Darling) for both Springfield and Evansville (using Minitab). (round to 3 decimal...

a) Find the AD (Anderson-Darling) for both Springfield and Evansville (using Minitab). (round to 3 decimal places)

b) Find the p-value for this test (using Minitab). (round to 3 decimal places)

City Price($)
Springfield 116480
Springfield 114746
Springfield 119697
Springfield 116625
Springfield 116877
Springfield 110206
Springfield 113552
Springfield 115015
Springfield 115058
Springfield 117310
Springfield 114553
Springfield 114770
Springfield 115249
Springfield 113548
Evansville 120070
Evansville 113786
Evansville 120177
Evansville 117433
Evansville 116873
Evansville 112948
Evansville 112260
Evansville 117860
Evansville 114275
Evansville 115145
Evansville 122196
Evansville 112747
Evansville 113422
Evansville 116383
Evansville 116277
Evansville 119371
Evansville 115739
Evansville 116609
Evansville 116977
Evansville 115778
Evansville 116861
Evansville 109303
Evansville 117424
Evansville 117552
Evansville 115460
Evansville 115295
Evansville 111973

Homework Answers

Answer #1

a) H0: The data follows Normal distribution

H1: The data does not follows Normal distribution

Let the los be alpha = 5%

Test Statistic AD = 0.242

Test Statistic AD = 0.426

b) P-value of Price($)_Evansville is 0.746 which is > alpha 0.05 so we accept H0

Thus we conclude that Price_Evansville is follows normal distribution.

P-value of Price($)_Evansville is 0.270 which is > alpha 0.05 so we accept H0

Thus we conclude that Price_Evansville is follows normal distribution.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A random sample of employees were put under the care of the company nurse because of...
A random sample of employees were put under the care of the company nurse because of high cholesterol readings. The nurse lectured them on the dangers of this condition and put them on a new diet. Data were observed on the cholesterol readings of the employees both before the new diet and one month after use of the diet began. We'd like to know if there is enough evidence that the mean cholesterol reading for all employees would be lower...
A cellular phone service provider is offering a new calling plan that it claims will result...
A cellular phone service provider is offering a new calling plan that it claims will result in an average savings of more than 20% for its customers who switch to the plan. To evaluate this claim, a consumer watchdog organization contacted a random sample of this provider's customers who enrolled in the new plan and computed their individual savings (as a percentage of their original monthly bill). PctSavings(%) 33.17 21.43 19.29 24.59 29.25 24.09 21.36 14.27 26.29 16.85 19.09 27.56...
1. Find: (In both parts, round to 2 decimal places) (a) Z0.07 (b) Z0.09 2. Find...
1. Find: (In both parts, round to 2 decimal places) (a) Z0.07 (b) Z0.09 2. Find zα/2 for the following confidence levels: (a) 93.6% (Round to 2 decimal places) (b) 88% (Give 3 decimal places here)
1. Find P(Z < -1.54). Round off to 4 decimal places. 2. Find P(Z > 1.45)....
1. Find P(Z < -1.54). Round off to 4 decimal places. 2. Find P(Z > 1.45). Round off to 4 decimal places. 3. Find P(-1.54 < Z < 1.45). Round off to 4 decimal places. 4. The monthly electric bills in a city are normally distributed with a mean of $125 and a standard deviation of $22. Find the x-value corresponding to a z-score of 1.65. 5. Find z if P(Z < z) = 0.028. 6. The weights of bags...
Round any numerical answers to 3 decimal places. 1.) A weight loss study measures each participant’s...
Round any numerical answers to 3 decimal places. 1.) A weight loss study measures each participant’s weight before the study and then 12 weeks into the study. A sample of 31 participants enrolled in the study and the mean difference in their weights (computed before – after) was found to be 4.1 pounds with a standard deviation of 3.2 pounds. In Minitab Express, conduct a paired means t-test to determine if there is evidence that the participants on average lost...
1. Find the area under the standard normal curve (round to four decimal places) a. To...
1. Find the area under the standard normal curve (round to four decimal places) a. To the left of  z=1.65 b. To the right of z = 0.54 c. Between z = -2.05 and z = 1.05 2. Find the z-score that has an area of 0.23 to its right. 3. The average height of a certain group of children is 49 inches with a standard deviation of 3 inches. If the heights are normally distributed, find the probability that a...
1.Find the value of the linear correlation coefficient r. Round to 3 decimal places. (47, 8),...
1.Find the value of the linear correlation coefficient r. Round to 3 decimal places. (47, 8), (46, 10), (27, 10) 2.Find the value of the linear correlation coefficient r. Round to 3 decimal places. (57, 156), (53, 164), (59, 163) 3. Find the value of the linear correlation coefficient r. Round to 3 decimal places. (2, 7), (4, 11), (5, 13)
A. The mean waiting time at the drive-through of a fast-food restaurant from the time an...
A. The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received is 84.3 seconds. A manager devises a new drive-through system that he believes will decrease wait time. He initiates the new system at his restaurant and measures the wait time for ten randomly selected orders. The wait times are provided in the table below. Based on the given data, is the new system effective?...
Using Appendix C-1 or Appendix C-2 find the p-value for each test statistic. (Round your answers...
Using Appendix C-1 or Appendix C-2 find the p-value for each test statistic. (Round your answers to 4 decimal places.) Test Statistic p-value (a) Right-tailed test z = +1.76 (b) Left-tailed test z = –1.60 (c) Two-tailed test z = –2.22
Find the value of za. a= 0.222 The value of z0.22 is (round to two decimal...
Find the value of za. a= 0.222 The value of z0.22 is (round to two decimal places as needed.) Using the Normal Distribution table.