Question

the events X and Y are mutually exclusive. Suppose P(X) = 0.13 and P(Y) = 0.11. What is the probability of either X or Y occurring? (Round your answer to 2 decimal places.) What is the probability that neither X nor Y will happen? (Round your answer to 2 decimal places.) Next

Answer 1

Solution :

Two two events X and Y are mutually exclusive.

P(X) = 0.13 and P(Y) = 0.11

a) We have to obtain P(X or Y).

If two events X and Y are mutually exclusive then,

P(X or Y) = P(X) + P(Y)

Hence, P(X or Y) = 0.13 + 0.11 = 0.24

P(X or Y) = 0.24

The probability of either X or Y occuring is 0.24.

b) We have to obtain P(neither X nor Y).

P(neither X nor Y) = 1 - P(X or Y)

P(neither X nor Y) = 1 - 0.24

P(neither X nor Y) = 0.76

The probability that neither X nor Y will happen is 0.76.

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