Question

Suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of 0.25 inches and a standard deviation of 0.05 inches. What proportion of woodlice have antenna lengths that are at least 0.18 inches? Round your answer to at least four decimal places.

Answer 1

Solution :

Given that,

mean = = 0.25

standard deviation = = 0.05

P (x 0.18 )

= 1 - P (x 0.18 )

= 1 - P ( x -  / ) ( 0.18 - 0.25 / 0.05)

= 1 - P ( z -0.07 / 0.05 )

= 1 - P ( z -1.4 )

Using z table

= 1 - 0.0808

= 0.9192

Proporation = 0.9192