Question

A random sample of 40 home theater system has a mean price of $142.00. Assume the...

A random sample of 40 home theater system has a mean price of $142.00. Assume the population standard deviation is $24.10. Use this information to a construct a 95% confidence interval for the population mean.

a. The critical corresponding to 95% level of confidence is ___________.

Homework Answers

Answer #1

142   1.96 ( 24.10 / 40 )

142   7.469

( 134.53 , 149.47 )

A 95 % CI for population mean is (134.53 , 149.47 )

----------------------------------------------------------

a) The Critical corresponding to 95 % level of confidence is 1.96

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 50 home theater systems has a mean price of ​$142.00. Assume the population standard deviation is ​$18.70. Construct a​ 90% confidence interval for the population mean.
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of ​$140.00 Assume the population standard deviation is ​$19.50. The 90% confidence interval is? The 95% confidence interval is?
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$140.00. Assume the population standard deviation is ​$16.20. Construct a 90% confidence interval for the population mean. The 90% confidence interval...
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the? 90% and? 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If? convenient, use technology to construct the confidence intervals. A random sample of 55 home theater systems has a mean price of ?$145.00. Assume the population standard deviation is ?$15.50. Construct a? 90% confidence interval for the population mean.
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of ​$147.00. Assume the population standard deviation is ​$19.40. Construct a​ 90% confidence interval for the population mean. The​ 90% confidence interval...
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the​90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 6060 home theater systems has a mean price of $129.00129.00. Assume the population standard deviation is ​$15.9015.90. Construct a​ 90% confidence interval for the population mean. The​ 90% confidence interval is...
A random sample of 40 students has a mean annual earnings of $3120. Assume the population...
A random sample of 40 students has a mean annual earnings of $3120. Assume the population standard deviation is $677. Construct a 95% confidence interval for the population mean, μ
you are given the sample mean and the population standard deviation. Use this information to construct...
you are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. interpret the results and compare the widths of the confidence intervals. if convenient, use technology to construct the confidence intervals. a random sample of 55 home theater systems has a mean price of $113.00. Assume the population standard deviation is $16.50
You are given the sample mean and the population standard deviation. Use this information to construct...
You are given the sample mean and the population standard deviation. Use this information to construct the? 90% and? 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If? convenient, use technology to construct the confidence intervals. A random sample of 60 60 home theater systems has a mean price of ?$ 130.00. Assume the population standard deviation is ?$ 16.20
a random sample of 40 transmission replavement costs find the mean to be $2520.00. Assume the...
a random sample of 40 transmission replavement costs find the mean to be $2520.00. Assume the population standard deviation is $400.00. A 95% confidence interval for the population mean repair cost is (2396.0,2644.0) Change the sample to n=80. Construct a 95% confidence interval for the population mean repair cost. which confidence interval its wider?