The experimenter is interested in the number of errors made by rats in a maze as a function of the kind of reward they are given. Group 1 receives 100% water reward; Group 2 receives a sugar solution; and Group 3 receives beer. Perform an ANOVA to determine if the difference among groups is likely to be statistically significant? Perform t-tests. Which groups have significantly different means at the .05 level of significance?
Group
1
2
3
4 13 26
5 15 21
3 12 19
9 15 21
6 15 23
5 16 24
7 14 19
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: u1 = u2 = u3
Alternative hypothesis: At-least one of the u is not equal.
Formulate an analysis plan. For this analysis, the significance level is 0.05.
Analyze sample data.
F statistics is given by:-
F = 110.109
Fcritical = 3.55
The P-value = less than 0.0001.
Interpret results. Since the P-value (almost 0) is less than the significance level (0.05), we have to reject the null hypothesis.
Conclusion:-
Reject H0, There is sufficient evidence for significant differences between the three kinds.
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