Two types of plastics are suitable for use by an electronics component manufacturer. The breaking strength of these plastics is very important. From a random sample size of n1=18, and n2=16, we obtained that X1-bar=151.2, S1=1.4 and X2-bar=152.3, S2=1.65.
Calculate a 95% confidence interval on the difference in means, assuming that the population variances are equal.
With 95% confidence, what is the left-value of the two-sided confidence interval on the difference in means?
Your Answer:
Confidence interval is :-
Lower Limit =
Lower Limit = -2.1654
Upper Limit =
Upper Limit = -0.0346
95% Confidence Interval is ( -2.1654 , -0.0346 )
Left Value = -2.1654
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