In a survey, the planning value for the population proportion is
p* = 0.31.
How large a sample should be taken to provide a 95% confidence interval with a margin of error of 0.05? (Round your answer up to nearest whole number.)
Solution,
Given that,
= 0.31
1 - = 1 - 0.31 = 0.69
margin of error = E = 0.05
At 95% confidence level
= 1 - 95%
= 1 - 0.95 =0.05
/2
= 0.025
Z/2
= Z0.025 = 1.96
sample size = n = (Z / 2 / E )2 * * (1 - )
= (1.96 / 0.05)2 * 0.31 * 0.69
= 328.68
sample size = n = 329
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