Question

According to a study, 21% of 507 female college students were on a diet at the...

  1. According to a study, 21% of 507 female college students were on a diet at the time of the study.

a) Construct a 99% confidence interval for the true proportion of all female students who were on a diet at the time of this study.

b) Explain what this interval means.

c) Is it reasonable to think that only 17% of college women are on a diet?

Homework Answers

Answer #1

a)

We know that 99% CI for true proportion is given by:

b)

We can say with 99% confidence that the true proportion lies in the above interval.

c)

Since the obtained 99% confidence interval contains 0.17, so at 1% level of significance, we can say that it is reasonable to think that only 17% of college women are on a diet.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
8) According to the US Census Bureau, 43% of men who worked at home were college...
8) According to the US Census Bureau, 43% of men who worked at home were college graduates. In a sample of 499 women who worked at home, 173 were college grads. What is the upper bound for 99% confidence interval for the proportion of women who work at home who are college grads? Round to 3 decimal places. 9) A medical researcher wants to construct a 99% confidence interval for the proportion of knee replacement surgeries result in complications. An...
According to the U.S. Census Bureau, 43% of men who worked at home were college graduates....
According to the U.S. Census Bureau, 43% of men who worked at home were college graduates. In a sample of 525 women who worked at home, 140 were college graduates. What is the upper bound for the 99% confidence interval for the proportion of women who work at home who are college graduates? Round to three decimal places (for example: 0.419). Write only a number as your answer.
According to the U.S. Census Bureau, 43% of men who worked at home were college graduates....
According to the U.S. Census Bureau, 43% of men who worked at home were college graduates. In a sample of 525 women who worked at home, 140 were college graduates. What is the upper bound for the 99% confidence interval for the proportion of women who work at home who are college graduates? Round to three decimal places (for example: 0.419). Write only a number as your answer.
Roll a pair of dice (one is red and the other is green). Let A be...
Roll a pair of dice (one is red and the other is green). Let A be the event that the red die is 4 or 5. Let B be the event that the green die is 1. Let C be the event that the dice sum is 7 or 8. Calculate P(A), P(B), P(C) Calculate P(A|C), P(A|B) Are the events A and C independent?                                                                                                                                     (20 points) Suppose box 1 has four black marbles and two white marbles, and box...
A group of 463 first-year college students were asked, “About how many hours do you study...
A group of 463 first-year college students were asked, “About how many hours do you study during a typical week?” The mean response is 15.3 hours. Assume that the study time is normally distributed with a sample standard deviation of 8.5 hours. Construct a 99% confidence level interval for the mean study time of all first-year students.
140 students at a college were asked whether they had completed their required English 101 course,...
140 students at a college were asked whether they had completed their required English 101 course, and 91 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( , )
140 students at a college were asked whether they had completed their required English 101 course,...
140 students at a college were asked whether they had completed their required English 101 course, and 91 students said "yes". Construct the 99% confidence interval for the proportion of students at the college who have completed their required English 101 course. Enter your answers as decimals (not percents) accurate to three decimal places. The Confidence Interval is ( , )
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a...
In a recent survey of 100 college students, 49% had received the HPV vaccine. Construct a 99% confidence interval for the proportion of college students who have received the vaccine. - Report the interval as a complete sentence in the context of the problem. - Would a 95% confidence interval be narrower or wider? Why? - Is it possible that the true proportion of vaccinate college students is over 50%? Why or why not?
1. Assume the students below are a random sample from the population of all college students...
1. Assume the students below are a random sample from the population of all college students 160 173 163 178 180 164 170 172 163 163 189 152 161 162 179 162 165 168 155 169 173 175 163 165 170 a. Construct a 99% confidence interval for the population mean college student height? Explain how you’ve got the numbers. b. Construct a 98% confidence interval for the population proportion of female college students. Explain how you’ve got the numbers....
Working at home: According to the U.S Census Bureau, 42% of men who worked at home...
Working at home: According to the U.S Census Bureau, 42% of men who worked at home were college graduates. In a sample of 514 women who worked at home, 158 were college graduates. (c) Based on the confidence interval, is it reasonable to believe that the proportion of college graduates among women who work at home is the same as the proportion of college graduates among men who work at home? Explain. yes/no, because 0.42 is/ is not contained in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT