Question

The data show the chest size and weight of several bears. Find the regression? equation, letting chest size be the independent? (x) variable. Then find the best predicted weight of a bear with a chest size of 51 inches. Is the result close to the actual weight of 595 pounds? Use a significance level of 0.05.

Chest size? (inches)	47	46	49	50	38	48
Weight? (pounds)	487	496	546	518	397	510

What is the regression? equation?

y = __ + __x

? (Round to one decimal place as? needed.)

Answer 1

X	Y	XY	X^2	Y^2
47	487	22889	2209	237169
46	496	22816	2116	246016
49	546	26754	2401	298116
50	518	25900	2500	268324
38	397	15086	1444	157609
48	510	24480	2304	260100

From the above calculated value we get the value are as:

n 6

sum(XY) 137925.00

sum(X) 278.00

sum(Y) 2954.00

sum(X^2) 12974.00

sum(Y^2) 1467334.00

b 11.3179

a -32.0607

Formula for regression equation are as:

y = -32.1 + 11.3x

when actual weight = 51

y = -32.1 + 11.3 *51

= 544.2