Question

Suppose that prices of women's athletic shoes have a mean of $75.15 and a standard deviation...

Suppose that prices of women's athletic shoes have a mean of $75.15 and a standard deviation of $17.89. What is the z-score of the mean
price $80.15 from a random sample of 50 pairs of women's athletic shoes

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that,

mean = = $75.15

standard deviation = =$17.89

n = 50

= $75.15

= / n = 17.89 / 50 = 2.5300

= $80.15

Z = - / = 80.15 - 75.15 / 2.5300 = 1.9763

z-score = 1.9763

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