Suppose 41% of the students in a university are baseball players. If a sample of 524 students is selected, what is the probability that the sample proportion of baseball players will be less than 44%? Round your answer to four decimal places.
Solution
Given that,
= [p ( 1 - p ) / n] = [(0.41 * 0.59) / 524 ] = 0.0215
P( < 0.44) =
= P[( - ) / < (0.44 - 0.41) / 0.0215]
= P(z < 1.40)
= 0.9192
Probability = 0.9192
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