An event has a 0.1230 probability of occurring. State as z score
and
SELECT ALL THAT APPLY
a. |
1.16 |
|
b. |
-1.16 |
|
c. |
1.6 standard deviations above the meen |
|
d. |
1.6 standard deviations below the mean |
The answer is:
We are dealing with the standard normal distribution, with parameters:
We need to find a z-score z so that the corresponding cumulative normal probability is equal to 0.123. Mathematically, z is such that:
The corresponding z score so that the cumulative standard normal probability distribution is 0.123 is
None of the other options are correct. This z score is basically 1.16 standard deviations below the mean, NOT 1.6 deviations below the mean.
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