If X = Normal (0, 4) the value of P(|X| > 2.2) is (use the normal table)
Select one:
a. 0.2713
b. 0.2321
c. 0.8438
d. 0.7286
Solution: We are given X follows Normal (0,4).
To find P(|X| > 2.2)
We can write P(|X| > 2.2) = P(X > 2.2) + P( X < -2.2) = 1 - P(X < 2.2) + P( X < -2.2)
= 1 - + [where is the cdf of a normal distribution with mean = 0 and standard devition = 2]
The required answer = 1 - 0.7088403 + 0.2911597 = 0.2713 [Rounded to 4 decimal places]
Ans. Option (a)
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