In estimating the mean monthly fuel expenditure, per household, a random sample of how many must be selected to be 99% confident and a population s. d. of 1.65, and margin of error, 5%.
Solution :
Given that,
Population standard deviation = = 1.65
Margin of error = E = 0.05
At 99% confidence level
= 1 - 99%
= 1 - 0.99 =0.01
/2
= 0.005
Z/2
= Z0.005 = 2.576
sample size = n = [Z/2* / E] 2
n = [ 2.576 * 1.65 / 0.05 ]2
n = 7226.36
Sample size = n = 7327
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