Question

# In a bumper test, three types of autos were deliberately crashed into a barrier at 5...

In a bumper test, three types of autos were deliberately crashed into a barrier at 5 mph, and the resulting damage (in dollars) was estimated. Five test vehicles of each type were crashed, with the results shown below. Research question: Are the mean crash damages the same for these three vehicles?

 Crash Damage (\$) Goliath Varmint Weasel 1,600 1,290 1,090 760 1,400 2,100 880 1,390 1,830 1,950 1,850 1,250 1,220 950 1,920

Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 1 decimal place, and other answers to 2 decimal places.)

You will need to open the Excel file and copy and paste the data from Excel into Minitab.

Make sure that the variable names are in the top gray row in Minitab and that data are entered into the numbers white rows

 One-Factor ANOVA Source SS df MS F p-value Treatment Error Total

Based on the given hypotheses, choose the right option.

H
0: μ1 = μ2 = μ3
H1: Not all the means are equal
α = .05

• Reject the null hypothesis if p-value < 0.05

• Reject the null hypothesis if p-value > 0.05

On the basis of the above findings, we cannot reject the null hypothesis.

• True

• False

using data >data analysis>one way ANOVA

we have

 Anova: Single Factor SUMMARY Groups Count Sum Average Variance Goliath 5 6410 1282 246320 Varmint 5 6880 1376 103580 Weasel 5 8190 1638 195170 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 340360 2 170180 0.93665 0.418802 3.885294 Within Groups 2180280 12 181690 Total 2520640 14

a )

 One-Factor ANOVA Source SS df MS F p-value Treatment 340360 2 170180 0.9367 0.4188 Error 2180280 12 181690 Total 2520640 14

Based on the given hypotheses, choose the right option.

H0: μ1 = μ2 = μ3
H1: Not all the means are equal
α = .05

• Reject the null hypothesis if p-value < 0.05

On the basis of the above findings, we cannot reject the null hypothesis.

• True