Question

In a bumper test, three types of autos were deliberately crashed into a barrier at 5 mph, and the resulting damage (in dollars) was estimated. Five test vehicles of each type were crashed, with the results shown below. Research question: Are the mean crash damages the same for these three vehicles?

Crash Damage ($)
Goliath	Varmint	Weasel
1,600	1,290	1,090
760	1,400	2,100
880	1,390	1,830
1,950	1,850	1,250
1,220	950	1,920

    Click here for the Excel Data File

Fill in the missing data. (Round your p-value to 4 decimal places, mean values to 1 decimal place, and other answers to 2 decimal places.)

You will need to open the Excel file and copy and paste the data from Excel into Minitab.

Make sure that the variable names are in the top gray row in Minitab and that data are entered into the numbers white rows

One-Factor ANOVA
Source	SS	df	MS	F	p-value
Treatment
Error
Total

Based on the given hypotheses, choose the right option.

H₀: μ₁ = μ₂ = μ₃
H₁: Not all the means are equal
α = .05

• Reject the null hypothesis if p-value < 0.05

• Reject the null hypothesis if p-value > 0.05

On the basis of the above findings, we cannot reject the null hypothesis.

• True

• False

Answer 1

using data >data analysis>one way ANOVA

we have

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
Goliath	5	6410	1282	246320
Varmint	5	6880	1376	103580
Weasel	5	8190	1638	195170
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	340360	2	170180	0.93665	0.418802	3.885294
Within Groups	2180280	12	181690
Total	2520640	14

a )

One-Factor ANOVA
Source	SS	df	MS	F	p-value
Treatment	340360	2	170180	0.9367	0.4188
Error	2180280	12	181690
Total	2520640	14

Based on the given hypotheses, choose the right option.

H0: μ1 = μ2 = μ3
H1: Not all the means are equal
α = .05

• Reject the null hypothesis if p-value < 0.05

On the basis of the above findings, we cannot reject the null hypothesis.

• True