1.Suppose the round-trip airfare between Boston and Orlando follows the normal probability distribution with a mean of $387.20 and a standard deviation of $68.50. What is the probability that a randomly selected airfare between Boston and San Francisco will be more than $450?
0.0788
0.3369
0.2033
0.1796
2.Suppose the round-trip airfare between Boston and Orlando follows the normal probability distribution with a mean of $387.20 and a standard deviation of $68.50. What is the probability that a randomly selected airfare between Boston and San Francisco will be less than $300?
0.3192
0.2005
0.4286
0.1015
Solution :
Given that ,
1) mean = = 387.20
standard deviation = = 68.50
P(x > 450) = 1 - p( x< 450 )
=1- p [(x - ) / < (450 - 387.20) /68.50 ]
=1- P(z < 0.92 )
= 1 - 0.8204 = 0.1796
probability = 0.1796
Answer = 0.1796
2)
P(x < 300 ) = P[(x - ) / < (300 -387.20) /68.50 ]
= P(z < -1.27 )
= 0.1015
probability =0.1015
Answer = 0.1015
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