Eleven adult black bears were used to evaluate the relationship between age and weight of adult black bears. Age was measured in years and weight was measured in pounds. Here is the data:
age 11 7 11 7 8 7 6 8 12 10 6
weight 119 88 112 121 123 136 92 88 130 112 110
The sample size for this analysis is n =___?____
The correlation coefficient, rounded to three places, is r
=___?____
The test statistic for testing whether the age and weight of adult
bears is positively correlated is: t(__?___) =___?____, when
rounded to 2 places.
The p-value is ___?___ when rounded to three places.
X | Y | XY | X² | Y² |
11 | 119 | 1309 | 121 | 14161 |
7 | 88 | 616 | 49 | 7744 |
11 | 112 | 1232 | 121 | 12544 |
7 | 121 | 847 | 49 | 14641 |
8 | 123 | 984 | 64 | 15129 |
7 | 136 | 952 | 49 | 18496 |
6 | 92 | 552 | 36 | 8464 |
8 | 88 | 704 | 64 | 7744 |
12 | 130 | 1560 | 144 | 16900 |
10 | 112 | 1120 | 100 | 12544 |
6 | 110 | 660 | 36 | 12100 |
Ʃx = | Ʃy = | Ʃxy = | Ʃx² = | Ʃy² = |
93 | 1231 | 10536 | 833 | 140467 |
Sample size, n = | 11 |
SSxx = Ʃx² - (Ʃx)²/n = | 46.7273 |
SSyy = Ʃy² - (Ʃy)²/n = | 2706.91 |
SSxy = Ʃxy - (Ʃx)(Ʃy)/n = | 128.455 |
Correlation coefficient, r = SSxy/√(SSxx*SSyy) = 0.361183 = 0.361
Null and alternative hypothesis:
Ho: ρ = 0 ; Ha: ρ ≠ 0
Test statistic : t = r*√(n-2)/√(1-r²) = 0.361*√(11-2)/√(1-0.361²) = 1.16
df = n-2 = 9
p-value = T.DIST.2T(1.16, 9) = 0.275
Decision: p-value > 0.05 , Fail to reject the null hypothesis.
There is no correlation between age and weight.
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