Must be done in Excel with the functions. Show how you got your answer!
The average height of young adult males has a normal distribution with standard deviation of 2.5 inches. You want to estimate the mean height of students at your college or university to within one inch with 93% confidence. How many male students must you measure?
Solution
standard deviation =s = =2.5
Margin of error = E = 1
At 93% confidence level the z is ,
Z/2= 1.812 ( Using z table )
sample size = n = [Z/2* / E] 2
n = ( 1.812* 2.5 / 1 )2
n =20.52
Sample size = n =21
#Excell
z | -1.81191 |
s | 2.5 |
E | 1 |
n=(z*s/E)^2 | 20.51888 |
Z=NORMSINV(0.07/2)
# 21 male students must you measure
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