Question

To estimate the average students' scores in a standardize test, a sample of 22 scores yielded...

To estimate the average students' scores in a standardize test, a sample of 22 scores yielded a mean of 70 and a standard deviation of 10. What is a lower limit for a 99% confidence interval for the population mean?

Homework Answers

Answer #1

Formula for lower limit of confidence interval for the population mean:

for 99% confidence level =(100-99)/100=0.01

/2 = 0.01/2 = 0.005

Given,

Sample size : n = 22

Sample mean : =70

Sample standard deviation : s = 10

Degrees of freedom = n-1=22-1=21

lower limit of 99% confidence interval for the population mean:

lower limit of 99% confidence interval for the population mean: 63.9634

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A professor wishes to estimate the variance of student test scores. A random sample of 18...
A professor wishes to estimate the variance of student test scores. A random sample of 18 scores had a sample standard deviation of 10.4. Find a 98% confidence interval for the population variance and interpret it. The lower confidence limit is _________ and the upper confidence limit is ________ . What assumption was necessary to calculate this interval estimate? Answer to 2 decimal places (PLEASE MAKE THE ANSWER ACCURATE)
A psychologist wants to estimate the standard deviation of IQ scores. It is widely believed that...
A psychologist wants to estimate the standard deviation of IQ scores. It is widely believed that IQ scores follow a normal distribution. Her random sample of 25 IQ scores has a mean of 99 and a standard deviation of 13.2 . Find the 99% confidence interval for the population standard deviation based on this sample. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If...
A psychologist wants to estimate the standard deviation of IQ scores. It is widely believed that...
A psychologist wants to estimate the standard deviation of IQ scores. It is widely believed that IQ scores follow a normal distribution. Her random sample of 25 IQ scores has a mean of 97.4 and a standard deviation of 17.2. Find the 99% confidence interval for the population standard deviation based on this sample. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to at least two decimal places. (If necessary,...
The mean scores of a random sample of 17 students who took a special test is...
The mean scores of a random sample of 17 students who took a special test is 83.5. If the standard deviation of the scores is 4.1, and the sample comes from normal population, find the point and the interval estimates of the population mean adopting a confidence level of 90%. Point estimate = _____ Interval estimate = _____ Please provide a clear solution
A random sample of n = 22 school children yielded the following data on their weight...
A random sample of n = 22 school children yielded the following data on their weight (lbs). sample mean: and sample standard deviation: s = 11. At a confidence level of 94%, calculate the margin of error in the estimate of the mean weight of this population of school children.
Randomly selected students participated in an experiment to test their ability to determine when one minute​...
Randomly selected students participated in an experiment to test their ability to determine when one minute​ (or sixty​ seconds) has passed. Forty students yielded a sample mean of 62.4 seconds. Assuming that σ=8.5 seconds, construct and interpret a 99​% confidence interval estimate of the population mean of all students. What is the 99​% confidence interval for the population mean μ​? ____<μ<_____
A college professor wants to estimate the difference in mean test scores of students who have...
A college professor wants to estimate the difference in mean test scores of students who have taken his statistics and genetics classes in the past 10 years. He selects a random sample of 20 student records from the statistics course and a random sample of 22 student records from the genetics course. These two samples were independent random samples. The study provided the results shown in the table below. Construct a 95% confidence interval for the true difference in population...
Scores on IQ test are normally distributed. A sample of 14 IQ scores had standard deviation...
Scores on IQ test are normally distributed. A sample of 14 IQ scores had standard deviation s=6. Construct a 99% confidence interval for the population standard deviation. The developerof the test claims that the population standard deviation is =7. Does this confidence interval contradict this claim?
From a random sample of 66 students in an introductory finance class that uses​ group-learning techniques,...
From a random sample of 66 students in an introductory finance class that uses​ group-learning techniques, the mean examination score was found to be 79.84 and the sample standard deviation was 2.5 For an independent random sample of 88 students in another introductory finance class that does not use​ group-learning techniques, the sample mean and standard deviation of exam scores were 73.38 and 8.5 respectively. Estimate with 95​% confidence the difference between the two population mean​ scores; do not assume...
Suppose the preliteracy scores of three-year-old students in the United States are normally distributed. Shelia, a...
Suppose the preliteracy scores of three-year-old students in the United States are normally distributed. Shelia, a preschool teacher, wants to estimate the mean score on preliteracy tests for the population of three-year-olds. She draws a simple random sample of 20 students from her class of three-year-olds and records their preliteracy scores (in points). 74,79,83,85,88,90,94,95,95,97,99,99,100,103,105,105,106,107,107,108 Calculate the sample mean (?⎯⎯⎯x¯), sample standard deviation (?s), and standard error (SE) of the students' scores. Round your answers to four decimal places. Determine the...