Question 4.
An automobile manufacturer is concerned about a possible recall of
its best-selling four-door sedan. If there were a recall, there is
a probability of 0.25 of a defect in the brake system, 0.18 of a
defect in the transmission,
0.17 of a defect in the fuel system, and 0.40 of a defect in some
other area. (a) What is the probability that the defect is the
brakes or the fueling system if the probability of defects in both
systems simultaneously is 0.15? (b) What is the probability that
there are no defects in either the brakes or the fueling
system?
solution:
a)
let P(A) be the probability that the defect in brake , P(A) = 0.25
let P(B) be the probability that the defect in fueling system , P(B) = 0.17
so probability of defect simultaniously occur in brake and fuel system =
we have to find the probability of defect in brake or fuel system =
= 0.25 + 0.17 - 0.15 = 0.27
b) we have to find the probability that there is no defect either in brake system or in fueling
so,
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