Given that,
The average score of 100 students taking a statistics test final with 70 with a standard deviation of seven.
Assuming a normal distribution, approximately how many scored less than 60.
i.e,
n=100
Mean ()=70
Standard Deviation ()=7
P(X < 60):
Here, we use standard normal variate
z=-1.4286
Therefore,
=1−P ( Z<1.4286 )
[Since, from the z-score table]
=1−0.9236
=0.0764
Therefore, P(X < 60) =0.0764
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