If n=13, ¯ x x¯ (x-bar)=50, and s=16, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.
< μ <
Solution :
degrees of freedom = n - 1 = 13 - 1 = 12
t/2,df = t0.10,12 = 1.356
Margin of error = E = t/2,df * (s /n)
= 1.356 * (16 / 13)
Margin of error = E = 6.0
The 80% confidence interval estimate of the population mean is,
- E < < + E
50 - 6.0 < < 50 + 6.0
44.0 < < 56.0
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