solution :
Given that,
Point estimate = sample mean = = 600
sample standard deviation = s = 90
sample size = n = 25
Degrees of freedom = df = n - 1 = 25 - 1 = 24
At 98% confidence level
= 1 - 98%
=1 - 0.98 = 0.02
/2
= 0.01
t/2,df
= 2.492
Margin of error = E = t/2,df * (s /n)
= 2.492 * (90 / 25)
Margin of error = E = 44.856
The 99% confidence interval estimate of the population mean is,
± E
600 ± 44.856
(555.144 , 644.856)
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