According to a recent Catalyst Census, 16% of executive officers were women with companies that have company headquarters in the Midwest. A random sample of 154 executive officers from these companies was selected. What is the probability that more than 20% of this sample is comprised of female employees? Please use Excel functions in your answer.
Using Excel<data<megastat<confidence interval<proportion
Here is the output:
Confidence interval - proportion | ||
80% | confidence level | |
0.16 | proportion | |
154 | n | |
1.282 | z | |
0.038 | margin of error | |
0.122 | lower confidence limit | |
0.198 | upper confidence limit |
From above output we get, z=1.22
or
Z value can be obtained using formula
Now using excel command "=1-normsdist(1.22)=0.11232"
Probability(more than 20% of this sample is comprised of female employees) | 0.111232437 |
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