Most air travellers now use e-tickets. Electronic ticketing allows passengers to not worry about a paper ticket, and it costs the airline companies less to handle than paper ticketing. However, in recent times, the airlines have received complaints from passengers regarding their e-tickets, particularly when connecting flights and a change of airlines were involved. To investigate the problem, an independent agency contacted a random sample of 20 airports and collected information on the number of complaints the airport had with e-tickets for the month of March. The information is reported below:
17 | 17 | 17 | 11 | 12 | 12 | 13 | 11 | 13 | 10 |
18 | 17 | 14 | 10 | 17 | 12 | 12 | 18 | 14 | 12 |
At the 0.02 significance level, can the agency conclude that the mean number of complaints per airport is less than 16 per month?
a. What assumption is necessary before conducting a test of hypothesis?
b. Not available in Connect.
c. Conduct a test of hypothesis and interpret the results.
H0 : μ ≥ 16; H1 : μ < 16;
H0 if t < . (Round the final answer to 3 decimal places.)
The value of the test statistic is . (Negative answer should be indicated by a minus sign. Round the final answer to 2 decimal places.)
H0. There is evidence to conclude that the mean number of complaints is less than 16.
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Answer:
From the data we find the mean as 13.85
SD of the data = 2.79615
SE = 2.79615/SQRT(20) = 0.62524
a)
It is reasonable to conclude that the population follows a normal distribution.
H0: u >= 16
H1: u < 16
b)
test stat t=(X-mean)/std error
= (13.85 - 16)/0.62524 = -3.44
=Tdist(-3.43868,19,1) = 0.001234
Since p value less than the 0.02
From the level of significance and calculated p-value, there is enough evidence to conclude that the mean number of complaints is less than 16
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