Question

A suggestion is made that the proportion of people who have food allergies and/or sensitivities is 0.48. You believe that the proportion is actually different from 0.48. The hypotheses for this test are Null Hypothesis: p = 0.48, Alternative Hypothesis: p ≠ 0.48. If you select a random sample of 26 people and 17 have a food allergy and/or sensitivity, what is your test statistic and p-value?

Question 11 options:

1)	Test Statistic: 1.774, P-Value: 0.962

2)	Test Statistic: 1.774, P-Value: 0.076

3)	Test Statistic: 1.774, P-Value: 0.924

4)	Test Statistic: -1.774, P-Value: 0.076

5)	Test Statistic: 1.774, P-Value: 0.038

Answer 1

The p-value is computed using excel using the formula:2*(1-NORM.DIST(1.774,0,1,1))

which gives us a p-value of 0.076

Therefore the correct answer is:

Option 2)

Test Statistic: 1.774, P-Value: 0.076

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