Question

Suppose Sabrina has 7 assistants, of whom she will pick two for a special assignment. The first person she names will carry the pizza; the second person will drive the car. Clark and Lois are two of these assistants. If she selects the names at random (draws the names one at a time out of a hat, for example), what are the chances she will just happen to pick Clark to carry the pizza and Lois to drive the car? (four decimal places)

Answer 1

First Selection: Clark to carry the pizza

Total Number of assistants: 7

P(Clark to carry the pizza ) = 1/7, since there are 7 assistants and Clark is one of them.

Second Selection: Lois to drive the car

Total Number of assistants: 6, since Clark has already been selected.

P( Lois to drive the car) = 1/6, since there are 6 remaining assistants and Clark is one of them.

So

The chances she will just happen to pick Clark to carry the pizza and Lois to drive the car is given by:

(1/7) X (1/6) = 0.0238

So,

Answer is:

0.0238