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An audit by a company attempts to estimate the proportion of misclassified documents. A simple random...

An audit by a company attempts to estimate the proportion of misclassified documents. A simple random sampling of 50 out of 250 documents revealed that all 20 documents were misclassified. Estimate the percentage of misclassified documents and calculate the 95% margin of error. Then, based on the results of the above ratio estimation, estimate the total number of misclassified documents and their variance.
Math   Statistics-And-Probability   
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Answer #1

Given a sample size of a random sample n = 50

number of misclassified documents x = 20.

the percentage of misclassified documents = p = (x/n)*100 = 20*100/50 = 40%

mean = p = 0.4

standard deviation = = = 0.069

95% margin of error = E =

alpha = 0.05

Z0.025 = 1.96

95% margin of error = E = 1.96*0.069 = 0.135

the total number of misclassified documents = 0.4*250 = 100

variance = = 0.4*0.6/250 = 0.00096 = 0.001

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