Question

4) Do hypothesis testing (I already did the t test on SPPS and provided the results down below)

Test grade of students against 88 - insert the SPSS output in the space below.

One-Sample Test
	Test Value = 88
	t	df	Sig. (2-tailed)	Mean Difference	95% Confidence Interval of the Difference
					Lower	Upper
Grade	-5.100	39	.000	-7.57500	-10.5794	-4.5706

One-Sample Statistics
	N	Mean	Std. Deviation	Std. Error Mean
Grade	40	80.4250	9.39418	1.48535

a- What would be the alternate hypothesis for the study?                                                

                               

b- What would be the null hypothesis?                                                         

               

c- What Level of Significance do you choose?                                              

d- What is the computed t critical value for the study?

• -5.100

                               

e- What is the P-value of the test?                  

               

f- What is the conclusion?

please provide the answers for question a-f and please explain why thank you !

Answer 1

a- What would be the alternate hypothesis for the study?   

Ha:

b- What would be the null hypothesis?

Ho:

c- What Level of Significance do you choose?   

t Level of Significance =alpha=.05

d- What is the computed t critical value for the study?

df=39

t critical for two tail is

=T.INV.2T(0.05,39)

=2.02269092

-5.100 is the test statistic which we got as

t=xbar-mu/SE

(80.4250-88)/(9.39418/sqrt(40))

=-5.099807

=-5.1

e- What is the P-value of the test?   

p=0.000

f- What is the conclusion?

alpha=0.05

p=0.000

p<0.05

Reject Ho

Accept Ha

Conclusion:

There is no sufficient statistical evidence at 5% level of signiifcance to conlcude that Test grade of students is88

meaning

est grade of students is against 88