Assume that when adults with smartphones are randomly selected, 52% use them in meetings or classes. If 15 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.
The probability is . (Type an integer or decimal rounded to four decimal places as needed.)
Let , X be the number of adults who use their smartphones in meetings or classes.
Here , X has binomial distribution with parameter n=15 and p=52%=0.52
The probability mass function of X is ,
; x=0,1,2,.........,n and q=1-p
= 0 ; otherwise
Now ,
Therefore , the probability that fewer than 3 of them use their smartphones in meetings or classes is 0.0023
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