Suppose the horses in a large stable have a mean weight of 873 lbs, and a variance of 17,161.
What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15 lbs if 50 horses are sampled at random from the stable? Round your answer to four decimal places.
Solution :
Given that,
mean = = 873
standard deviation = = 131
= / n = 131 / 50 = 18.5262
= P[(-15) /18.5262 < ( - ) / < (15) / 18.5262)]
= P(-0.81 < Z < 0.81)
= P(Z < 0.81) - P(Z < -0.81)
= 0.791 - 0.2090
= 0.5820
Probability = 0.5820
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