Question

Use this regression model I created to answer to answer this question it has 2 parts:

2. (a) Interpret the slope estimates in this regression model, that is interpret the impact Female Youth LR on U5MR, and interpret the R2 [square] respectively.

(b) Using the results for this regression model, the predicted value of U5MR(U5MR-No. of deaths of children 0-5 yrs, per 1000 live births) when Female Youth LR =80. (Female Youth LR-Percent of females 15-24 literate)

Regression Statistics
Multiple R	0.784
R Square	0.615
Adjusted R Square	0.612
Standard Error	24.310
Observations	132
ANOVA
	df	SS	MS	F	Significance F
Regression	1	122810.6827	122810.7	207.8077	9.78137E-29
Residual	130	76827.70366	590.9823
Total	131	199638.3864
	Coefficients	Standard Error	t Stat	P-value	Lower 95%	Upper 95%	Lower 90.0%	Upper 90.0%
Intercept	183.3557	10.07001258	18.20809	1.405E-37	163.4333843	203.27802	166.673119	200.038281
98.85624013	-1.6353292	0.113442129	-14.4155	9.781E-29	-1.85976089	-1.410898	-1.8232642	-1.4473942

Answer 1

a) here the slope estimate of female youth LR is -1.6353 , that means for a unit change in Female youth LR , there 1.6353 change in U5MR, here the sign is negative implies, for a unit increase in female youth LR, there is a decrease in U5MR by 1.6353.

here R2 = .615 that means 61.5%

ie., 61.5% change in the dependent variable U5MR is explained by the independent variable female youth LR in the model. that is the variable female youth LR accounts for the 61.5% change in U5MR.

b) here y^ =183.3557 - 1.6353292*x

given x =80

so the predicted value of U5MR = 183.3557-1.6353292*80 =52.529364 =52.53