Question

Use this regression model I created to answer to answer this question it has 2 parts:...

Use this regression model I created to answer to answer this question it has 2 parts:

2. (a) Interpret the slope estimates in this regression model, that is interpret the impact Female Youth LR on U5MR, and interpret the R2 [square] respectively.

(b) Using the results for this regression model, the predicted value of U5MR(U5MR-No. of deaths of children 0-5 yrs, per 1000 live births) when Female Youth LR =80. (Female Youth LR-Percent of females 15-24 literate)

Regression Statistics
Multiple R 0.784
R Square 0.615
Adjusted R Square 0.612
Standard Error 24.310
Observations 132
ANOVA
df SS MS F Significance F
Regression 1 122810.6827 122810.7 207.8077 9.78137E-29
Residual 130 76827.70366 590.9823
Total 131 199638.3864
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 90.0% Upper 90.0%
Intercept 183.3557 10.07001258 18.20809 1.405E-37 163.4333843 203.27802 166.673119 200.038281
98.85624013 -1.6353292 0.113442129 -14.4155 9.781E-29 -1.85976089 -1.410898 -1.8232642 -1.4473942

Homework Answers

Answer #1

a) here the slope estimate of female youth LR is -1.6353 , that means for a unit change in Female youth LR , there 1.6353 change in U5MR, here the sign is negative implies, for a unit increase in female youth LR, there is a decrease in U5MR by 1.6353.

here R2 = .615 that means 61.5%

ie., 61.5% change in the dependent variable U5MR is explained by the independent variable female youth LR in the model. that is the variable female youth LR accounts for the 61.5% change in U5MR.

b) here y^ =183.3557 - 1.6353292*x

given x =80

so the predicted value of U5MR = 183.3557-1.6353292*80 =52.529364 =52.53

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