Take a sample of 40 ACT scores with a sample mean of 21 and a known population standard deviation of 5.
Construct a 95% Confidence Interval for the mean ACT score.
n = 40
SE = /
= 5/
= 0.7906
= 0.05
From Table, critical values of Z = 1.96
Confidence Interval:
21 (1.96 X 0.7906)
= 21 1.5495
= ( 19.4505 ,22.5495)
Confidence Interval:
19.4505 < < 22.5495
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