Question
355 in a sample of 1000 individuals said they would vote for candidate A in the...
355 in a sample of 1000 individuals said they would vote for candidate A in the next election. Obtain the 95% confidence interval for the proportion of voters who would vote for candidate A. Question options: [0.025 , 0.685] [0.225 , 0.485] [0.125 , 0.585] [0.325 , 0.385]
Homework Answers
Answer #1
Here correct option is last option.
[0.325,0.385]
For detailed I have attached the solution.
Not the answer you're looking for?
Similar Questions
In a randomly selected sample of 500 registered voters in a community, 240 individuals say that...
In a randomly selected sample of 500 registered voters in a
community, 240 individuals say that they plan to vote for Candidate
Y in the upcoming election.
Find a 95% confidence interval for the proportion of the
registered voter population who plan to vote for Candidate Y.
(Round your answers to three decimal places.)
Find a 98% confidence interval for the proportion of the
registered voter population who plan to vote for Candidate Y.
(Round your answers to three decimal...
In a random sample of 400 registered voters, 144 indicated they plan to vote for Candidate...
In a random sample of 400 registered voters, 144 indicated they
plan to vote for Candidate A.
Determine a 95% confidence interval for the proportion of all
the registered voters who will vote for Candidate A.
Value from the appropriate table=
Margin of error=
Lower limit of C.I.=
Upper limit of C.I.=
In a randomly selected sample of 400 registered voters in a community, 160 individuals say that...
In a randomly selected sample of 400 registered voters in a
community, 160 individuals say that they plan to vote for Candidate
Y in the upcoming election.
(a) Find the sample proportion planning to vote for Candidate Y.
(Round your answer to two decimal places.)
(b) Calculate the standard error of the sample proportion. (Round
your answer to three decimal places.)
(c) Find a 95% confidence interval for the proportion of the
registered voter population who plan to vote for...
A survey of 250 voters was conducted to determine who they would vote for in an...
A survey of 250 voters was conducted to determine who they would
vote for in an upcoming election for sheriff. Fifty-five percent
said they would vote for Longmire.
A/ What is the best unbiased estimate of the population
proportion that will vote for Longmire (in other words, what is
?)
B/ Find the margin of error E that corresponds to a 90% confidence
Interval.
C/ Construct the 90% confidence interval about the population
proportion p.
D/ Based on your results,...
In an election exit poll (N = 1,768), 898 respondents said they voted for Candidate A....
In an election exit poll (N = 1,768), 898 respondents said they
voted for Candidate A. Is Candidate A going to win the election
(more than 50% of votes needed to win)? Use α = 0.1 for a
hypothesis testing. Questions 33 to 38 are based on this
example.
33. What’s the proportion of respondents in the poll
voted for Candidate A?
34. What would be the H1 for the example?
A. The percentage of respondents in the poll voted...
A random sample of ?=1000 registered voters and found that 520 would vote for the Republican...
A random sample of ?=1000 registered voters and found that 520
would vote for the Republican candidate in a state senate race. Let
? represent the proportion of registered voters who would vote for
the Republican candidate.
Consider testing
?0:?=.50
??:?>.50
(a) The test statistic is ?z =
(b) Regardless of what you acutally computed, suppose your
answer to part (a) was z = 1.28. Using this z, p-value =
In a recent poll, 134 registered voters who planned to vote in the next election were...
In a recent poll, 134 registered voters who planned to
vote in the next election were asked if they would vote for a
particular candidate and 80 of these people responded that they
would. We wish to predict the proportion of people who will vote
for this candidate in the election.
a) Find a point estimator of the proportion who would vote for
this candidate.
b) Construct a 90% confidence interval for the true proportion
who would vote for this...
In a recent poll, 134 registered voters who planned to vote in the next election were...
In a recent poll, 134 registered voters who planned to vote in
the next election were asked if they would vote for a particular
candidate and 80 of these people responded that they would. 1. 1.
We wish to predict the proportion of people who will vote for this
candidate in the election.
a) Find a point estimator of the proportion who would vote for
this candidate.
b) Construct a 90% confidence interval for the true proportion
who would vote...
6) A newspaper polls 58 voters to ask which candidate for mayor the supported in an...
6) A newspaper polls 58 voters to ask which candidate for mayor
the supported in an upcoming election.
Of the 58 people polled, 20 said that they intended to vote for
Candidate Jones.
a) Find a 99% confidence interval for the true proportion of
people in the city who plan to vote for Candidate Jones.
b) Provide the margin of error of the interval as your
answer.
Round your answer to 4 decimal places.
A random sample of likely voters showed that 35% planned to vote for Candidate A, with...
A random sample of likely voters showed that 35% planned to
vote for Candidate A, with a margin of error of 2% points and with
90% confidence.
Which of the following statements best describes the
confidence interval for the percentage of voters who plan to vote
for Candidate A.
I am 90% confident that the population percentage of voters
supporting Candidate A is between 33% and 37%.
I am 90% confident that the population percentage of voters
supporting Candidate A...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 35 minutes ago
asked 39 minutes ago
asked 39 minutes ago
asked 47 minutes ago
asked 47 minutes ago
asked 48 minutes ago
asked 55 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago