Question

The mean birth weight of male babies born to 121 mothers taking a vitamin supplement is

3.633.63

kilograms with a standard deviation of

0.630.63

kilogram. Use a 0.05 significance level to test the claim that the mean birth weight of all babies born to mothers taking the vitamin supplement is equal to 3.39 kilograms, which is the mean for the population of all male babies.

State the null and alternative hypotheses. Find the z-score and the P value and make a conclusion.

Answer #1

**Here' the answer to the question. Please let me know in
case you've problem understanding the solution**

Xbar = 3.63

Stdev = 0.63

n = 121

alpha = .05

Pop. Mean = 3.39

The null and alternate hypothesis is :

Ho: Mu = 3.39

Ha: Mu !=3.39

Lets calculate the Z test-statistic

= (Xbar-Mean)/(Stdev/sqrt(n))

= (3.63-3.39)/(.63/sqrt(121))

= +4.1905

Z score is 4.1905

p-value = P(|z|>4.1905) = 2.7837E-05

[we make use Z table to convert to a probability value or the Excel
formula =NORMSDIST(z)]

This is less than .05

**Conclusion: No, claim that the mean birth weight of all
babies born to mothers taking the vitamin supplement is equal to
3.39 kilograms is FALSE**

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